7b^2+29b+4=0

Solution for 7b^2+29b+4=0 equation:

Simplifying
7b2 + 29b + 4 = 0

Reorder the terms:
4 + 29b + 7b2 = 0

Solving
4 + 29b + 7b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(4 + b)(1 + 7b) = 0

Subproblem 1
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(1 + 7b)' equal to zero and attempt to solve:

Simplifying
1 + 7b = 0

Solving
1 + 7b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 7b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 7b = 0 + -1
7b = 0 + -1

Combine like terms: 0 + -1 = -1
7b = -1

Divide each side by '7'.
b = -0.1428571429

Simplifying
b = -0.1428571429
Solution
b = {-4, -0.1428571429}